1.5x^2=10x

Solution for 1.5x^2=10x equation:

1.5x^2=10x

We move all terms to the left:

1.5x^2-(10x)=0

a = 1.5; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·1.5·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*1.5}=\frac{0}{3}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*1.5}=\frac{20}{3}
=6+2/3
$